Distinct user_id
WebThe SELECT DISTINCT statement is used to return only distinct (different) values. … WebMar 20, 2024 · SELECT DISTINCT user_id, post_id, post_content FROM some_table …
Distinct user_id
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WebMar 8, 2024 · PostHog will then pull their anonymous ID (e.g. 17b845b08de74-033c497ed2753c-35667c03-1fa400-17b845b08dfd55) and associate it with the ID you passed in (my_user_12345). From now on, all events PostHog sees with ID 17b845b08de74-033c497ed2753c-35667c03-1fa400-17b845b08dfd55 will be attributed … WebSELECT name , COUNT (user_id) FROM books b LEFT JOIN books_users u ON u.book_id = b.id GROUP BY 1 ORDER BY 2 ASC. You actually get some books with 0 values, because nobody has started reading them. But then for avoiding duplicated values from same users we add the DISTINCT, however, all books now again have at least a …
WebI am working in Yii and, I have a table named : visits It has two foreign keys : from_user_id and to_user_id which are linked to the 'user' table. Now the table visits has many same 'from_user_id' and I want to get retrieve them in Yii as DISCTINCT. This is my code : However, I am not able to get Web2 days ago · 1 Answer. You can use aggregation to get for each user their max group_id and COUNT () window function to count for each of the returned max group_id s the number of users: SELECT DISTINCT MAX (group_id) AS group_id, COUNT (*) OVER (PARTITION BY MAX (group_id)) AS members FROM group_users GROUP BY user_id; This query …
WebDistinct definition, distinguished as not being the same; not identical; separate … WebApr 14, 2024 · 然后使用COUNT(DISTINCT b.user_id)计算当天有登录记录的用户数,使用COUNT(DISTINCT a.user_id)计算次日有登录记录的用户数。该SQL语句中,首先通过LEFT JOIN将当天和次日的登录记录进行关联,并筛选出当天和次日均有登录记录的用户。最后将次日有登录记录的用户数除以当天有登录记录的用户数并乘以100 ...
WebAug 29, 2024 · Now I want to display the percentage of the number of tickets per user. I tried this: WITH number_of_tickets AS ( SELECT user_id, COUNT (user_id) AS number_of_tickets_per_user FROM tickets GROUP BY user_id ) SELECT number_of_tickets_per_user, ROUND ( (COUNT (user_id) * 100.0) / (SELECT COUNT …
WebThis block is a great way to analyze event data, which can come from Google Analytics, Segment, Snowplow, or a custom event-tracking system (like a table that has a row for every user event). Expected Output. This block helps us segment customers into monthly, weekly, and daily active users — in other words, for each date, the users who have ... hcv 2 pdf downloadhttp://distinctid.com/ hc-v180k full hd camcorderWebApr 14, 2024 · 然后使用COUNT(DISTINCT b.user_id)计算当天有登录记录的用户数,使 … golden brown mucusWebSelect distinct id, name from sql_distinct order by id, name; The below example shows a … golden brown musicWebMar 1, 2015 · SELECT DISTINCT user_id FROM events 123 WHERE DATE(event_time) = ' 2024-04-06 '; Note that we use user_id instead of amplitude_id because user_id is the identifier that your project recognizes (e.g. user email addresses, login names, etc) while amplitude_id is Amplitude's internal ID for users, which is not meaningful outside of … golden brown metallic paintWebNov 8, 2024 · DELETE FROM wp_usermeta WHERE user_id> 1 AND user_id NOT IN (SELECT DISTINCT post_author FROM wp_posts) AND user_id NOT IN (SELECT DISTINCT user_id FROM wp_comments); DELETE FROM wp_links WHERE link_owner> 1 AND link_owner NOT IN (SELECT DISTINCT post_author FROM wp_posts) AND … hcu wichitaWebSep 9, 2015 · Hi, I have table A(year int, month int, user varchar(20)), and I am trying to write a view that would show number of distinct users in the last 3 months, last 6 months, last 9 months and last 12 months (all from the most recent year/month) in following format: 3 months 6 mont · Hi Pedja, Please see below sample. CREATE TABLE [A] ( [Year] … hcv 2 year tool